Problem 1 :
The point P(3, 8) is on the graph of y = bx, where b > 1. The corresponding point P’ on the graph of y + 3 = bx + 1 is
A) (2, 11)
B) (2, 5)
C) (4, 11)
D) (4, 5)
Solution :
Problem 2 :
The function y = f(x) has a domain of {x| 2 ≤ x ≤ 6, x ∈ R} and a range of
{y| -4 ≤ y ≤ 8, y ∈ R}, The function undergoes the transformation y = -f(½x).
The domain and range of the transformed function are shown in row :
Solution :
Problem 3 :
The graph of y = f(x) is transformed into the graph of y = g(x), shown below.
An equation for g(x) in terms of f(x) is
A) g(x) = f(2x) + 10
B) g(x) = f(½x) + 10
C) g(x) = 2f(2x)
D) g(x) = 2f(½x)
Solution :
Problem 4 :
If Point A(–3, 4) is a point on the graph of y = f(x), then find the corresponding image point, A’, on the graph of
An equation for g(x) in terms of f (x) is
A) (3, 1)
B) (3, 7)
C) (-5, 1)
D) (-5, 1)
Solution :
Problem 5 :
The loudness of a sound is related to the logarithm of the ratio of the measured intensity, I, to a reference intensity, I0. The loudness, L, of a sound is measured in decibels, dB, and can be determined using the following formula.
During an international soccer tournament in 2010, a noisemaker called the vuvuzela had a measured loudness of 127 dB at full volume.
If the intensity of the sound of the vuvuzela is 5 000 times greater than the intensity of the sound of a lawn mower, then the measured loudness of the lawn mower, to the nearest decibel, is
A) 3 dB
B) 37 dB
C) 90 dB
D) 123 dB
Solution :
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